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v^2-10v-144=0
a = 1; b = -10; c = -144;
Δ = b2-4ac
Δ = -102-4·1·(-144)
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{676}=26$$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-26}{2*1}=\frac{-16}{2} =-8 $$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+26}{2*1}=\frac{36}{2} =18 $
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